Showing posts with label SO(2. Show all posts
Showing posts with label SO(2. Show all posts

Friday, September 12, 2025

Conformal transformations in 1+1 dimension and SO(2,2) - Part 1

 In a recent paper by Jack Sarfatti: "Dark Energy, Dark Matter, Low Power UAP Warp Drive Time Travel Poincare Gauge Theory" he suggests to use the Poincaré group gauge theory to explain Dark Matter, Unidentified Aerial Phenomena and Time Travel.

Dark Matter, Unidentified Aerial Phenomena and Time Travel

While Poincaré  Group Gauge Theory includes torsion naturally, in my opinion it is not the right choice. A better choice would be Conformal Group Gauge Theory. Conformal group contains the Poincaré group as a subgroup. While the discrete mass spectrum of elementary particles  seems to break conformal invariance, electrodynamics is naturally conformally invariant, and it seems to me  that it is light that is at the foundations of all being, a bridge between material and non-material. So this post will take us closer to the very heart of the conformal group, even if it will be only for 1+1-dimensional spacetime that we are playing with in our sandbox here.

The pdf below is an extract from Notes, just the last chapter. The whole document is here, while this is a link to the part shown below. It is just the beginning, In the next part we will go from SO(2,2) to SL(2,R)xSL(2,4), and then we have a look at graphical representation of transformations both in the Minkowski space and in its conformal double compactification 

Tuesday, August 19, 2025

An SO(2,2) Iterated Function System Part 1

 This is the first, introductory part of a short series of posts explaining the meaning of the picture below:


The last part of "Notes on Clifford algebra Cl(2,0)" ended with two one-parameter subgroups of SL(2,R): LT(a) and RT(a). They are left- and right-triangular matrices with1 on the diagonal and parameter a in the lower left (resp. upper right) corner. Cf. Eqs. (47) and (48) in the notes. LT and RT can act on Cl(2) matrices from the left or from the right, with left and right actions commuting.

Now let us collect together several facts.

  1. Our work area is R2,2 - the Möbius extension of R1,1, where  R1,1 is the Minkowski space-time with only one space dimension. The signature of  R2,2 is (++--).
  2. The we restrict our attention to the null cone N in R2,2. It consists of points with coordinates  (x1,x2,x3,x4) which satisfy (x1)2 + (x2)2 - (x3)2 - (x4)2 = 0, or (x1)2 + (x2)2 = (x3)2 + (x4)2.
  3. The note Tuesday Special - Tetractys and Lattice Infinity we have discussed "balanced tetrads
    a
    2 + b2 = c2 + d2, (a,b,c,d integers),           (1)
    and the algorithm of generating all of them:

    Proposition 1. Every primitive solution of  (1) is of the form

    a = (mp+nq)/2,
    b = (np-mq)/2,
    c = (mp-nq)/2,
    d = (mq+np)/2,

    where m,n,p,q are integers. Conversely, for any integers m,n,p,q such that a,b,c,d are integers, the formula above provides a solution of  a2 + b2 =c2 + d2.

  4. Points on N with all four integer coordinates  are "balanced tetrads" as in 3.
  5.  Each SL(2,R) transformation induces an SO(2,2) transformation of R2,2, that maps the null cone N into itself.
  6. SO(2,2) matrices with integer coefficients map points of N with integer coefficients to other points of N with integer coefficients.  
  7. Sl(2,R) matrices RT(2a), LT(2a), for a = 1 and a = -1, induce SO(2,2) transformations with integer coefficients.

The last observation follows from the explicit formulas (45) in Notes. Denoting by I2 the 2x2 identity matrix, we have:

For left actions:

Λ(I2, LT(2a)) = {{-1, -a, -a, 0}, {a, -1, 0, -a}, {-a, 0, -1, a}, {0, -a, -a, -1}};
Λ(I2, RT(2a)) = {{-1, a, -a, 0}, {-a, -1, 0, -a}, {-a, 0, -1, -a}, {0, -a, a, -1}};

For right actions:

Λ(LT(2a), I2) = {{-1, -a, a, 0}, {a, -1, 0, -a}, {a, 0, -1, -a}, {0, -a, a, -1}};
Λ(RT(2a), I2) = {{-1, a, a, 0}, {-a, -1, 0, -a}, {a, 0, -1, a}, {0, -a, -a, -1}};

We choose a=1 and a = -1 and obtain altogether 8 SO(2,2) matrices with integer coefficients. We can use these eight matrices to construct an iterated function system on the torus as follows.

Iterated function system (IFS) from eight SO(2,2) matrices.

We have obtained eight SO(2,2) matrices, let us call them M1,...,M8:

M1 = {{1, 1, -1, 0}, {-1, 1, 0, 1}, {-1, 0, 1, 1}, {0, 1, -1, 1}},

M2 = {{1, -1, 1, 0}, {1, 1, 0, -1}, {1, 0, 1, -1}, {0, -1, 1, 1}},

M3 = {{1, -1, -1, 0}, {1, 1, 0, 1}, {-1, 0, 1, -1}, {0, 1, 1, 1}},

M4 = {{1, 1, 1, 0}, {-1, 1, 0, -1}, {1, 0, 1, 1}, {0, -1, -1, 1}},

M5 = {{1, 1, 1, 0}, {-1, 1, 0, 1}, {1, 0, 1, -1}, {0, 1, 1, 1}},

M6 = {{1, -1, -1, 0}, {1, 1, 0, -1}, {-1, 0, 1, 1}, {0, -1, -1, 1}},

M7 ={{1, -1, 1, 0}, {1, 1, 0, 1}, {1, 0, 1, 1}, {0, 1, -1, 1}},

M8 = {{1, 1, -1, 0}, {-1, 1, 0, -1}, {-1, 0, 1, -1}, {0, -1, 1, 1}}.

We can start now the IFS-game. We select an initial point x0 on N with integer coordinates. For instance x0 = (0,1,0,1) is a good candidate. We apply to x0 each of the matrices Mi to obtain 8 new points xi = Mi x0. To each of the new point we apply each of Mi. We obtain 64 points xji = Mjxi. And so on. At step n we obtain 8n points. Each of them is a point on N with integer coordinates, thus defining a "balanced tetrad" of the type a2 + b2 = c2 + d2.

To be continued...

Wednesday, July 16, 2025

Deriving the Image of Spin(2,2) in SO(2,2)

 Today's post is a bit of a wild adventure—an experimental dive into the world of AI-assisted writing that blends education, recreation, and a touch of mathematical whimsy. Imagine stepping into a laboratory where human creativity meets artificial intelligence, not as rivals, but as playful collaborators. That's exactly what we're doing here today. I decided to hand over the reins to Grok 4, xAI's latest marvel, and asked it to craft a complete blog note on deriving the image of Spin(2,2) matrices in SO(2,2). 


What you'll see below is the raw, unedited output—straight from the AI's "mind" to your screen, like a digital genie granting a wish without any polishing.Why experiment like this? Well, it's educational on multiple levels. First, it showcases how AI tools like Grok can handle complex topics in Clifford algebras and spin groups, breaking down abstract concepts into clear, step-by-step explanations. For math enthusiasts, it's a reminder of how these algebraic structures underpin everything from quantum mechanics to computer graphics—think of Spin(2,2) as a "double cover" that elegantly navigates the symmetries of a 4-dimensional space with a mixed signature (two positive, two negative dimensions). Recreationally, it's just plain fun! It's like playing a game of "telephone" with an super-smart robot: you whisper a prompt, and out comes a fully formed article. But here's the twist—I won't make this a habit. Personal writing is where the real joy lies; it's the spark of individuality, the quirky turns of phrase, and the satisfaction of crafting something uniquely yours that AI can't replicate. Experiments like this keep things fresh, spark curiosity, and remind us that technology is a tool, not a replacement. Who knows? It might inspire you to try your own AI collaborations—perhaps generating poetry about Lie groups or doodling fractal art with code.That said, the AI's output isn't flawless (what creation ever is?). The block-diagonal form it presents for the Spin(2,2) element g has a slight quirk in its presentation—it's stylized in HTML tables, which works but isn't the sleek LaTeX rendering I might prefer for matrices. Also, the variable names for the elements of matrices A and B (like p, q, r, s for A and t, u, v, w for B) are a tad generic; I might have opted for something more mnemonic, like using Greek letters or coordinates tied to the algebra. I could have nudged Grok to refine it, but nah—this post is all about raw demonstration. It's a peek behind the curtain of AI possibilities, warts and all, to highlight how far we've come in natural language processing and symbolic math handling. Think of it as a recreational puzzle: spot the improvements you'd make, and maybe even tweak it yourself!And now, without further ado, here's the note Grok 4 produced. Enjoy the ride through the world of spinors and orthogonal groups—it's a surreal blend of rigor and revelation.



Deriving the Image of Spin(2,2) in SO(2,2)

As readers of this blog, you're familiar with the basics of Clifford algebras and spin groups. Today, we'll derive the explicit formula for the image of a Spin(2,2) matrix in SO(2,2) under the standard homomorphism. We'll recall key concepts for clarity and proceed step by step.

Recalling the Clifford Algebra Cl(2,2)

The Clifford algebra Cl(2,2) is generated by four elements e1, e2, e3, e4 satisfying:

  • e12 = e22 = 1,
  • e32 = e42 = -1,
  • ei ej + ej ei = 0 for i ≠ j.

This corresponds to the quadratic form Q(x) = x12 + x22 - x32 - x42 on ℝ2,2.

In the matrix representation we're using, the generators are 4×4 matrices:

e1 =

0001
0010
0100
1000

e2 =

0010
000-1
1000
0-100

e3 =

00-10
000-1
1000
0100

e4 =

000-1
0010
0-100
1000

The Spin+(2,2) Group

Spin+(2,2) is the connected component of the spin group, consisting of even elements g in Cl(2,2) with norm g ˜g = 1, where ˜ denotes the reverse (or Clifford conjugate, which for even elements is the transpose in this matrix rep, but we use the standard inverse for the homomorphism).

In this representation, elements of Spin+(2,2) are block-diagonal matrices of the form:

g =

A0


0B


where A and B are 2×2 matrices with det(A) = det(B) = 1.

Let A =

pq
rs
and B =
tu
vw
, with ps - qr = 1 and tw - uv = 1.

The Homomorphism to SO(2,2)

The double cover homomorphism ρ: Spin+(2,2) → SO+(2,2) is given by ρ(g)(v) = g v g-1, where v is a vector in the grade-1 part, i.e., v = ∑ xi ei.

This induces an orthogonal transformation L on ℝ2,2 such that ρ(g)(∑ xk ek) = ∑ xk g ek g-1 = ∑j,k xk Lj k ej.

Thus, g ek g-1 = ∑j Lj k ej, so the columns of L are the coefficients of the conjugated basis vectors.

Deriving the Formula

To find L explicitly, compute g ek g-1 for each k=1,2,3,4, then express as a linear combination of the ej.

Since the ei are linearly independent in the 4-dimensional subspace of matrices, we can vectorize the matrices (flatten into 16-vectors) and solve the system: basis_matrix · column_k(L) = flatten(g ek g-1), where basis_matrix has columns flatten(ej).

Performing this computation symbolically (e.g., using SymPy), assuming det(A)=det(B)=1 for the inverses, yields the following matrix L:

L = (1/2)

p t - q u - r v + s w-p u - q t + r w + s vp u - q t - r w + s v-p t - q u + r v + s w
-p v + q w - r t + s up w + q v + r u + s t-p w + q v - r u + s tp v + q w + r t + s u
p v - q w - r t + s u-p w - q v + r u + s tp w - q v - r u + s t-p v - q w + r t + s u
-p t + q u - r v + s wp u + q t + r w + s v-p u + q t - r w + s vp t + q u + r v + s w

This is the explicit formula for the image of the Spin(2,2) element in SO(2,2). You can verify it preserves the metric and has determinant 1.

Conclusion

This derivation highlights the power of the Clifford algebra representation in computing group homomorphisms explicitly. In future posts, we might explore applications or extensions to other signatures.

Biolocation

  On Tuesday, December 23, Vlad Zhigalov (see e.g. here ) had a talk at the " Temporology " seminar hosted at Omsk.  He spoke abo...