Showing posts with label trace-class. Show all posts
Showing posts with label trace-class. Show all posts

Sunday, March 16, 2025

Spin Chronicles Part 50: Lurking infinity II

 We continue from Part 49.

Is all quantum? Or it is rather like this:

Let us recall the notation used there: H is a separable Hilbert space, with the scalar product (x,y), A = B(H) is the von Neumann algebra of all bounded operators on H, ρ is a (faithful) density matrix in the ideal of trace-class operators, B2(H) is the ideal of Hilbert-Schmidt operators with the scalar product <X,Y> = Tr(X*Y), we have B1(H)⊂B2(H)⊂B(H), en (n=1,2,....) is an orthonormal basis consisting of eigenvectors of ρ in H, so that

ρ = n pn Pn, pn>0,  ∑n pn = 1,

where Pn are orthogonal projections on en

Notice that if H is infinite-dimensional, then limn pn = 0 (Why?), so that, in this case 0 is an accumulation point in the spectrum of ρ.

It is useful to have an orthonormal basis in the Hilbert algebra B2(H). To this end we define em,n∈B2(H)

em,n ≐ |em)(en|

where

|em)(en| x = (en,x)em.

Exercise 1. Prove that em,n∈B2(H).

Then they indeed form an orthonormal basis in B2(H).

Exercise 2. Prove the last statement. Hint: to show that we have a basis consider the space of all finite linear combinations of Emn. Use the fact that a subspace is dense in a Hilbert space if and only if the only vector orthogonal to all vectors of the subspace is the zero vector.

Exercise 3☺. Show that, with the notation as above, Pn = em,n.

In the following we shall employ a convenient notation used by Connes and Rovelli in their paper [1]. Given an element a∈A, it can be considered as a bounded operator in B(H). But if it is a Hilbert-Schmidt operator, it is an element of the Hilbert space B2(H). In the later case we will write it as | a >. Thus, for example,

  Ωρ = | ρ½ >        (1)

The representations π and π' of A on B2(H) become resp.

π(a)| b > = | ab >, π'(a)| b > = | ba >.

For the scalar product we can write

<a,b> = < a | b > = Tr(a*b).

The Tomita-Takesaki construction provides us with two (super-) operators: the anti-unitary involution J, and the unitary "Tomita flow" s ⟼ Uρ(s), s ∈ R.

The involution J

We consider first the anti-unitary (super-) operator

J: B2(H) → B2(H),

defined by

J | a > = | a* >.                     (2)

We immediately get the anti-unitary property (How?):

<JS , JT> = cc(<T , S>),    S,T in B2(H),

where cc stands for the complex conjugate.

We also have J2 = 1 (the identity operator). Moreover, we have

JΩρ = Ωρ , for any density matrix ρ.

Notice that, in our context, J does not depend on ρ - it is "universal".

We have

Jπ(A)J = π'(A).

Indeed, for any a∈A, b∈B2(H), we have

Jπ(a)J| b > = Jπ(a)| b* > = J| ab* > = | ba*> = π'(a*) | b >.

Therefore Jπ(a)J = π'(a*), and the equality Jπ(A)J = π'(A) follows (Why?). But π'(A) = π(A)', therefore J transforms the von Neumann algebra π(A) into its commutant, and vice versa (as it follows from J2=1).

Tomita's thermal flow

Tomita's flow Uρ(s) is defined by the formula:

Uρ(s)| a > = | ρisaρ-is >, a∈B2(H), s∈R.      (3)

The formula above requires an explanation. Here it comes. First of all what is ρis? Here we use Fig. 1 of Part 49, with integrals replaced by infinite sums. Since
ρ = Σn pn Pn, is a spectral resolution of ρ, ρis is defined as:

ρis = n pnis Pn.

But what is λis (here for λ>0)? It can be defined as

λis = eis log λ,

where log stands for the natural logarithm.

For λ>0 and s real, it is a complex number of modulus 1, thus nothing special. We thus have

ρis = n eis log pn Pn.          (4)

It follows then from the last statement in Fig 1 that ρis is a unitary operator in B(H) (How?). Moreover, denoting

Uρ(s) = ρis  = eis log(ρ),       (5)

we have (How?)

Uρ(s) Uρ(s') = Uρ(s+s'),

so that we have a one-parameter group of unitary operators on H. Denoting

αs(a) = Uρ(s) a Uρ(s)*,       aA,

we have a one-parameter group of *-automorphisms of A. It is called the group of modular automorphisms. It is this group that is called the Tomita modular flow. We notice that (Why?)

Uρ(s) Ωρ = Ωρ,

so that the vector Ωρ, representing the state, is invariant under Uρ(s). We can also write it as the invariance of the state ω under the modular flow

ω(αs(a)) = ω(a),     sR.

References

[1] A. Connes, C. Rovelli, "Von Neumann algebra automorphisms and time-thermodynamics relation in generally covariant quantum theories", Class. Quantum Grav. 11 (1994) 2899 .

To be continued ....

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