Sunday, October 13, 2024

The Spin Chronicles: Painting Quantum Tori (Part 2)

 The Mysterious Phase of Quantum Mechanics: A Spin on Reality

In quantum mechanics, the phase of a wave function is treated like that distant cousin you only hear about but never meet—it's assumed to be unobservable. The star of the show is the amplitude, or more precisely, the square of its modulus. That’s the part we can see and measure. Textbooks say: "Only this, and nothing else, is observable." And sure, that’s one way of looking at it.


But let's face it—opinions in quantum mechanics are as varied as the stars in the sky. Physicists are like travelers in a big, wide world, each with their own unique map of how quantum mechanics works. In fact, no two physicists share exactly the same view—unless, of course, one of them is just crunching numbers from a cookbook of equations. And even then, not all cookbooks are created equal!

The Wave Function and the Art of Spin

We often talk about the "wave function" when we’re trying to pinpoint the location of an object. You know, that quantum object that seems to be everywhere and nowhere at the same time? But today, let's zoom in on something a little more grounded: spin.

Now, spin is a different beast. The object in question stays put, but its spin axis can change direction. This is where we enter the world of the state vector. For spin-½ particles, this vector is made up of four real numbers: XX, YY, ZZ, and WW. Their squares add up to one, which is pretty neat. If you’re a fan of complex numbers (and let’s be real, who isn’t?), it’s just two complex numbers whose modulus squares also sum to one. The conversion between the two is surprisingly simple:

z1=X+iYandz2=Z+iW

This lets us break the real part and imaginary part down like so:

X=Re(z1),Y=Im(z1),Z=Re(z2),W=Im(z2)

Easy, right? Well, it gets more interesting.

From Numbers to Angles: Theta, Phi, and Psi

Instead of juggling numbers like XX, YY, ZZ, and WW, it’s often more intuitive to use angles—

θϕ, and ψ


These angles help specify the position of our vector on a three-dimensional sphere that lives in four-dimensional space. So, the coordinates transform into:

X=sin(ϕ2)cos(ψ),Y=sin(ϕ2)sin(ψ)X = \sin\left(\frac{\phi}{2}\right)\cos(\psi), \quad Y = \sin\left(\frac{\phi}{2}\right)\sin(\psi)
Z=cos(ϕ2)cos(ψ+θ),W=cos(ϕ2)sin(ψ+θ)Z = \cos\left(\frac{\phi}{2}\right)\cos(\psi + \theta), \quad W = \cos\left(\frac{\phi}{2}\right)\sin(\psi + \theta)

The Projection into 3D Space

At this point, we need to bring things back into the three-dimensional world we're used to. To do that, we use something called stereographic projection, which I’ve covered in detail a couple of blog posts ago. This allows us to map the points from four-dimensional space into our three-dimensional world. The result gives us familiar coordinates:

x(θ,ϕ,ψ)=sin(ϕ2)cos(ψ)1cos(ϕ2)sin(ψ+θ)x(\theta, \phi, \psi) = \frac{\sin\left(\frac{\phi}{2}\right)\cos(\psi)}{1 - \cos\left(\frac{\phi}{2}\right)\sin(\psi + \theta)} y(θ,ϕ,ψ)=sin(ϕ2)sin(ψ)1cos(ϕ2)sin(ψ+θ)y(\theta, \phi, \psi) = \frac{\sin\left(\frac{\phi}{2}\right)\sin(\psi)}{1 - \cos\left(\frac{\phi}{2}\right)\sin(\psi + \theta)} z(θ,ϕ,ψ)=cos(ϕ2)cos(ψ+θ)1cos(ϕ2)sin(ψ+θ)z(\theta, \phi, \psi) = \frac{\cos\left(\frac{\phi}{2}\right)\cos(\psi + \theta)}{1 - \cos\left(\frac{\phi}{2}\right)\sin(\psi + \theta)}

What's the Deal with Theta, Phi, and Psi?

So what’s the physical meaning behind these angles? In our lab, the zz-axis points upwards (think of it as "North" on a globe), and the ϕ angle measures the tilt of the spin axis—essentially, it's latitude. θ is the longitude, with the x-axis as 0 degrees and the y-axis at 90 degrees (or π/2 if you’re feeling mathematically fancy).

But the ψ angle? That’s where things get interesting. Psi is like the "invisible phase," a ghostly presence that Richard Feynman himself couldn't ignore when he wrote about spin. And today, we’re going to shine a light on this elusive angle.

Painting the Invisible: Great Circles and Wheels

Our mission here is to bring these invisible aspects of the state vector to life. As we vary psi from 0 to 2π2\pi, something magical happens—a closed curve appears. This curve, on a three-dimensional sphere in four-dimensional space, is known as a "great circle."

You’ve seen great circles before—they’re the big loops you get when slicing through a globe. Meridians and the equator are great circles. The same idea applies here, except now we’re in four dimensions. These invisible great circles can be projected back into our familiar 3D space as... wait for it... circles! That’s why this blog post is titled Invisible Wheels.

A Torus of Invisible Wheels

Now, imagine a large torus made of these invisible circles—these are called Villarceau circles, similar to what you’d find in the architecture of Strasbourg Cathedral. But here’s the catch: each of these circles is perceived as just a single point—a spin pointing in a particular direction (theta,phitheta, phi). The psi phase, which determines where we are on that circle, remains hidden from us.

Want to see what these circles look like? I whipped up some visualizations in Mathematica, and here’s what I got: 

X[theta_, phi_, psi_] = Sin[phi/2]*Cos[psi];
Y[theta_, phi_, psi_] = Sin[phi/2]*Sin[psi];
Z[theta_, phi_, psi_] = Cos[phi/2]*Cos[psi + theta];
W[theta_, phi_, psi_] = Cos[phi/2]*Sin[psi + theta];
ParametricPlot3D[Table[
  {X[i*Pi/18, Pi/4, p]/(1 - W[i*Pi/18, Pi/4, p]), 
   Y[i*Pi/18, Pi/4, p]/(1 - W[i*Pi/18, Pi/4, p]), 
   Z[i*Pi/18, Pi/4, p]/(1 - W[i*Pi/18, Pi/4, p])}, {i, 0, 35}], {p, 0,
   2 Pi}, PlotRange -> All, PlotStyle -> White, Background -> Black]

Still not satisfied? I’m currently experimenting with MathMod to generate even better images, but for now, this will have to do.

Wrapping Up

In the next post, we’ll explore how these tori and invisible wheels interact with each other. We’ll dive even deeper into their physical interpretation, so stay tuned!

For those of you curious about 4D visualizations, check out Dimensions Math. Search for "Hopf fibration"—it’s the key to everything we’ve discussed, even though I haven’t officially mentioned it... yet.

Until next time, keep spinning those wheels—visible or not!

P.S. 14-10-24 10:36 Here is my attempt to draw both circles and tori using Povray:


P.S. 14-10-24 Saša  asked me to share the Mathematica code for my Hopf fibration games. Here it is. It is experimental, never completely finished.

P.S.14-10-24 15:28 Responding to Bjab's request in a comment under the previous post, I am measuring the speed and direction of aether wind today (I am stretching a little bit):

Peaceful 6.2 km/h (7.8 km/h in gusts), NE.

P.S. 14-10-24 19:18 Reading Mary Rose Barrington, Ian Stevenson and Zofia Weaver  - "A World In A Grain Of Sand. The Clairvoyance Of Stefan Ossowiecki",  McFarland & Company (2005). There, p. 41, description by by Gustave Geley of an experiment done by Charles Richet in Warsaw, in April 1922:
Not quite the situation described below.. You will need to adjust the details...

Experiment 4 {related by Richet} This was done in rather different conditions. Several people were present, and we were reduced to giving Ossowiecki words and numbers in very poor conditions of scientific control. Generally speaking he was very successful. 
So, at a good distance from Ossowiecki, using a scrap of paper, taking all necessary precautions to ensure that no one saw what I was doing, I wrote the word TOI [the familiar form of"you" linguistically equivalent to "thou" or "thee"]. Then I screwed up the paper so as to make a little ball; Ossowiecki took it in the palm of his hand, his hand being placed in mine. 

After three or four minutes he said, "It's a number." I remain impassive. "It's very short." Same impassivity. "It's a word." I make no gesture and say nothing. 

Then he adds, "I see aT." And then adds some details "There are two little strokes on the cross-bar of the T," which was absolutely true, because I had added two little vertical strokes to make the T more legible. I said, "That's very good." 

Then he says, "There is a digit, a zero." I say, "Very good." He adds, "There is a 1." Then he adds, very quietly, "Ce n'est pas MOl." (It's not ME.) I try to give the impression that I have not heard that. Then Ossowiecki says, "Give me a piece of paper and I'll write it down." And he wrote "T 0 1." 

Only then I unfolded my piece of paper, very crumpled, still in Ossowiecki's hand. Richet then calculates the probabilities, and argues how Ossowiecki could not possibly have been guided by his own gestures. Richet once again reviews and dismisses chance, collusion, telepathy and visual hyperacuity as explanations. 
...
Everything indicates that awareness of things comes to Ossowiecki by touch. Ossowiecki makes repeated efforts at handling, kneading, chafing the envelope. It is through his fingers and his skin, not by his eyes, his ears or sense of smell that he exercises his divining sense. We must therefore associate cryptaesthesia with touch; it is a tactile hyperaesthesia, but an immensely potent hyperaesthesia that we do not understand. One must even postulate that the written letters carry in themselves some property other than the external properties perceptible by our normal senses.
Real Stefan Ossowiecki

How shall I explain with physics and math these experiments? 

P.S. 14-10-24 20:30 Day od the Comet!

Tsuchinshan-ATLAS at  8:10 today (Credit: Adam)

P.S. 14-10-24 18:54 Just created a new image for the paper I am working on:




P.S. 15-10-24 17:29 With the help from Abderrahman Taha, the creator of MathMod, I was finally able to draw the invisible psi circles with MathMod:



46 comments:

  1. "In our lab, the z -axis points upwards (think of it as "North" on a globe), and the ϕ angle measures the tilt of the spin axis—essentially, it's latitude. θ is the longitude, with the x-axis as 0 degrees "

    I don't understand it.

    ReplyDelete
    Replies
    1. The point (x,y,z)=(1,0,0) has θ=0.

      Delete
    2. "The point (x,y,z)=(1,0,0) has θ=0."
      That does not help.

      What about point (x,y,z) = (0,0,1) ?

      Delete
    3. θ is undefined for this point. Much like the longitude of the North Pole.

      Delete
    4. You write about something like spin axis - what do you mean by that?
      How does the coordinate system on the map - (x,y,z) - relate to the three-dimensionality we perceive (x1,y1,z1).

      Delete
  2. "I am measuring the speed and direction of aether wind"

    There is no aether wind essentially.

    ReplyDelete
    Replies
    1. Correct statement is: there is no official evidence for non-zero speed. That is not the same as "there is no aether wind". Ther may be one, but needs very special devices to detect it. Does it make sense?

      Delete
    2. If we are in a river and we do not see its banks or bridges, we cannot tell whether it is flowing.

      Delete
    3. But if we have with us a smartphone with GPS, and if we know how to use it - then we can easily tell.

      Delete
    4. We assume that spin is in a certain "state". There is a method to describe this state with numbers. These numbers depend on the selected axes in the laboratory. Like vector coordinates describing the direction the Moon is now. I am giving a prescription how to describe a state vector for a given laboratory coordinate system. I was not discussing so far how these naber change whe we rotate the laboratory axes.

      Delete
    5. *numbers* Cat is in front of the monitor and I do not see what I am writing. Sorry.

      Delete
    6. Well, that may be impossible, because even if we know our speed relative to satellites (GPS) we do not even know what our speed is relative to the water (ether), so we are not able to determine its speed.

      Delete
  3. Again, what do you mean by "spin axis?

    ReplyDelete
    Replies
    1. Thanks for asking. To fully address your question I will need a fresh mind. And that will be tomorrow.

      Delete
    2. With fresh mind I realized that I need to think more. And I have a problem with the paper I am working on now, a problem, I think, related to your question. So, perhaps I will try to answer your question in my next post, though this is optimistic. We will see.

      Delete
    3. That is I know the standard answer ("spin structure" etc.), but I am not happy with the standard answer. I am seeking something more satisfying for me.

      Delete
    4. В 4-мерном пространстве можно не только вращаться, но ещё и двигаться поступательно. Так сказать, спин в динамике.

      Delete
    5. Perhaps. But first this: your sentence "vector field ∂ϕ is given in the basis of vector fields formed by paired rotations" makes no sense for me.
      So, please, explain fully.

      Delete
    6. Аркадиуш, меня тоже это не устраивало, поэтому я значительно переделал это место. Посмотрите отредактированный вариант.

      Delete
    7. " Then, a dynamical system with
      an inertial manifold on a 3-dimensional unit sphere is given by a system of equations".

      What that means?
      1) A dynamical system is ONE vector field, noy three!
      2) This is not on the sphere! Trajectories of these vector fileds are not on the sphere!
      3) The vector fields ∂ϕx, ∂ϕy, ∂ϕz do not form the algebra of quaternions. You did not correct your error from the first version.

      Fix it Igor!

      Delete
    8. По первому пункту согласен. По второму пункту нет понимания. Я имл ввиду ортогональность к радиальному векторному полю в метрике 4-мерного евклидова пространства. А вы о чём говорите? По третьему пункту пока полностью не согласен. Если только опять чего то не напутал.

      Delete
    9. "Я имл ввиду ортогональность к радиальному векторному полю в метрике 4-мерного евклидова пространства"

      Then provide the proof of this orthogonality. Evidently it is very easy for you. So show us this proof!

      Delete
    10. "По третьему пункту пока полностью не согласен."

      Then prof isomorphism of the algebra of your vector fields with the quaternion algebra! Evidently it is very easy for you. So show us this proof!

      Delete
    11. Хорошо. Но чуть позже, сейчас нет доступа к компьютеру.

      Delete
    12. Общая формула, связывающая линейные векторные поля и представляющие их матрицы
      ∂φ=A(x_1,x_2,x_3,x_4)^{T}(∂x_1,∂x_2,∂x_3,∂x_4)
      Теперь конкретно
      ∂φ_x=A_x(x_1,x_2,x_3,x_4)^{T}(∂x_1,∂x_2,∂x_3,∂x_4)=(-x_2,x_1,-x_4,x_3)
      ∂φ_y=A_y(x_1,x_2,x_3,x_4)^{T}(∂x_1,∂x_2,∂x_3,∂x_4)=(-x_4,-x_3,x_2,x_1)
      ∂φ_z=A_z(x_1,x_2,x_3,x_4)^{T}(∂x_1,∂x_2,∂x_3,∂x_4)=(-x_3,x_4,x_1,-x_2)
      ∂ρ=A_0(x_1,x_2,x_3,x_4)^{T}(∂x_1,∂x_2,∂x_3,∂x_4)=(x_1,x_2,x_3,x_4)
      где векторные поля изображаются без базиса
      (∂x_1,∂x_2,∂x_3,∂x_4), который однако подразумевается на соответствующем месте.
      С помощью скалярного произведения (свёртки) векторных полей легко проверяется ортогональность
      (∂φ_x,∂ρ)=(∂φ_y,∂ρ)=(∂φ_z,∂ρ)=0
      которая для представляющих их матриц оборачивается справедливым для алгебры кватернионов требованием
      A_x*A_x=A_y*A_y=A_z*A_z=-A_0
      В свою очередь ортогональность
      (∂φ_x,∂φ_y)=(∂φ_x,∂φ_z)=(∂φ_y,∂φ_z)=0
      эквивалентна антикоммутативности матриц
      A_x*A_y+A_y*A_x=0
      A_x*A_z+A_z*A_x=0
      A_y*A_z+A_z*A_y=0
      что также является обязательным требованием для алгебры кватернионов.
      Я перемножал эти векторные поля, получались нули. Матрицы не перемножал, но в этом и нет необходимости.

      Delete
    13. OK. I will check. But what about the fact that you write: " a dynamical system with an inertial manifold on a 3-dimensional unit sphere", but trajectories of these fields (1.1.7) are NOT on the sphere.
      And what about the fact that a dynamical system is just one vector field, and not three vector fields?

      Delete
    14. "Я перемножал эти векторные поля, получались нули".
      How do you multiply vector fields? What do you mean by a product of two vector fields???

      Delete
    15. Тут я глупость написал, но после вашего замечания осознал и обещаю это место исправить.

      Delete
    16. Igor, the fields \phi_x and \phi_y do NOT anti-commute. They commute. You already know this. And you "глупость написал" again!

      Delete
    17. Перемножал в каждой точке, кроме нулевой, вектор оного поля на вектор другого. Что касается обнаруженной вами коммутативности, то это означает, что ортогональность полей не равносильна антикоммутативности. Подобрать подходящие поля не сложно, но я подумаю ещё на эту тему.

      Delete
    18. That is not how you compose vector fields. "Матрицы не перемножал". So do it! Check on matrices and you will see!

      Delete
    19. Перемножил матрицы и увидел, что опять я наступил на те же грабли. На этот раз вместо первого поля надо взять произведение второго на третье. Что касается свертки векторных полей, то не вижу тут ничего незаконного. Это просто проверка на ортогональность в каждой точке пространства.

      Delete
    20. Получается, что вместо A_x надо брать -A_x и все будет OK

      Delete
    21. " space with two infinity points Lines of time red, lines of space white. Lines of time and lines of space meet at two different singular (infinity) points. ".
      But didn't you say they are mutually "orthogonal"? Makes no sense to me.
      So, when are you going to fix these "lies" in your paper??? You should not keep online your paper with "lies". This way show no respect for other people, you know? Why didn't you correct instantly, when your "lies" were pointed to you by me and by Bjab?

      Delete
    22. "Получается, что вместо A_x надо брать -A_x и все будет OK"
      If Ax commutes with Ay, then -Ax also commutes with Ay. Igor, are you sober?

      Delete
    23. Ничего не понял. Что это за линии в двух цветах? Похоже вы путаете ортогональность в евклидовой метрике и метрике Минковского. Если вы находите ошибки в тексте, то это хорошо, но это не означает, что я намеренно лгу. И почему я должен закрыть доступ к тексту из-за того, что он сырой. Может кто-то ещё захочет покритиковать его.

      Delete
    24. Одна рюмка коньяка в честь Дня Матери. Так что вполне трезв и уже осознал - ляпнул не подумавши.

      Delete
  4. "P.S. 14-10-24 Saša asked me to share the Mathematica code for my Hopf fibration games. Here it is. It is experimental, never completely finished."

    Thank you very much.
    Even if experimental, it produces cool stuff, thanks again.

    ReplyDelete
    Replies
    1. I am happy that it gives you some fun! It certainly gives me!

      Delete
    2. Аркадиуш, я перепроверил. Все матрицы прекрано себе антикоммутируют.

      Delete
    3. 1) Wchich matrices?
      2) Please, write them down.
      3) Please, explain how they relate to your vector fields.
      4) Sleep well. Good night!

      Delete
    4. Доброе утро.
      A_x=
      0-1 0 0
      1 0 0 0
      0 0 0-1
      0 0 1 0

      A_y=
      0 0 0-1
      0 0-1 0
      0 1 0 0
      1 0 0 0

      A_z=
      0 0-1 0
      0 0 0 1
      1 0 0 0
      0-1 0 0

      ∂φ_x=A_x(x_1,x_2,x_3,x_4)^{T}(∂x_1,∂x_2,∂x_3,∂x_4) =
      (-x_2,x_1,-x_4,x_3)
      ∂φ_y=A_y(x_1,x_2,x_3,x_4)^{T}(∂x_1,∂x_2,∂x_3,∂x_4) =
      (-x_4,-x_3,x_2,x_1)
      ∂φ_z=A_z(x_1,x_2,x_3,x_4)^{T}(∂x_1,∂x_2,∂x_3,∂x_4) =
      (-x_3,x_4,x_1,-x_2)
      где векторные поля изображены без базисных элементов.

      Delete
    5. Поправка. Надо строку на столбец, а не наоборот.
      ∂φ = (∂x_1,∂x_2,∂x_3,∂x_4) A (x_1,x_2,x_3,x_4)^{T}

      Delete
    6. And do you get (1.1.10) from these matrices? Or you get something else?

      Delete
    7. Я укоротил текст. Теперь это на месте (1.1.6)

      Delete
    8. And do you get (1.1.6) from these matrices? Or you get something

      Delete

Thank you for your comment..

The Spin Chronicles (Part 3): Spin frames

What’s a Spin Axis, Anyway? This post was inspired by a question from Bjab, who asked: "What do you mean by ‘spin axis’?" Well, bu...